| ⇦ |
| ⇨ |
The radius of gyration of a solid sphere of radius r about a certain axis is r. The distance of this axis from the centre of the sphere is
Options
(a) r
(b) 0.5r
(c) √(0.6)r
(d) √(0.4)r
Correct Answer:
√(0.6)r
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The identical cells connected in series are needed to heat a wire of length one meter
- An open pipe resonates with a tuning fork of frequency 500 Hz. It is observed
- Two bodies A and B have masses 20 Kg and 5 Kg respectively. Each one is acted
- 64 drops of mercury, each charged to a potential of 10 V, are combined
- According to Hook’s law, force is proportional to
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The identical cells connected in series are needed to heat a wire of length one meter
- An open pipe resonates with a tuning fork of frequency 500 Hz. It is observed
- Two bodies A and B have masses 20 Kg and 5 Kg respectively. Each one is acted
- 64 drops of mercury, each charged to a potential of 10 V, are combined
- According to Hook’s law, force is proportional to
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Using parallel axis theorem ,
I =Icm(about the centre of mass) + M(mass of the sphere)h2. where h is the required distance of the axis from centre of sphere
MK2 = 2/5 MR2. + Mh2
K2= 2R2/5 + h2
R2 = 2R2/5. + h2. (given that. K=R. )
3R2/5 = h2
Which gives h=√3/5R2
h=√0.6. R. (Answer)