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What will be the correct relationship between free energy and equilibrium constant K of a reaction?
Options
(a) ∆G = -RT ln K
(b) -∆G = 0
(c) ∆G = -RT⁻¹ ln K
(d) ∆G = -RT⁻² ln K
Correct Answer:
∆G = -RT ln K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When enthalpy and entropy change for a chemical reaction are – 2.5 x 10³ cals
- Consider the modes of transformations of a gas from state ‘A’ to state ‘B’
- Certain bimolecular reactions which following first order kinetics are called
- Orthonitrophenol is steam volatile while para-isomer is not. This is because of
- Vanadium (III) oxide is a strong
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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