| ⇦ | 
| ⇨ |
Primary,secondary and tertiary amines can be distinguished by
Options
(a) Schiff’s test
(b) Fehling’s test
(c) Tollent’s test
(d) Hinsberg’s test
Correct Answer:
Hinsberg’s test
Explanation:
This reaction takes place in the presence of Na+EtOH/Reduction HNO₂ and K₂Cr₂O₇/H₂SO₄
CH₃-C≡N → CH₃-CH₂-NH₂→CH₃-CH₂-OH→CH₃COOH.
Related Questions: - Number of chiral carbon in β-D-(+) glucose is
- 1-bromopropane on treatment with ethanolic potassium hydroxide produces
- Unpleasent smelling carbylamines are formed by heating alkali and chloroform with
- The number of carbon atoms in Buckminsterfullerene is
- Oxidation number of iodine in IO₃⁻, IO₄⁻, KI and I₂ respectively are
Topics: Organic compounds containing Nitrogen
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Number of chiral carbon in β-D-(+) glucose is
- 1-bromopropane on treatment with ethanolic potassium hydroxide produces
- Unpleasent smelling carbylamines are formed by heating alkali and chloroform with
- The number of carbon atoms in Buckminsterfullerene is
- Oxidation number of iodine in IO₃⁻, IO₄⁻, KI and I₂ respectively are
Topics: Organic compounds containing Nitrogen (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply