| ⇦ | 
| ⇨ |
The correct order in which the O–O bond length increases in the following is
Options
(a) H₂O₂ < O₂ < O₃
(b) O₃ < H₂O₂ < O₂
(c) O₂ < O₃ < H₂O₂
(d) O₂ < H₂O₂ < O₃
Correct Answer:
O₂ < O₃ < H₂O₂
Explanation:
Bond length of O–O in O₂ = 1.21 Å
Bond length of O–O in O₃ = 1.278 Å
Bond length of O–O in H₂O₂ = 1.49 Å
Therefore correct order of O–O bond length is O₂ < O₃ < H₂O₂
Related Questions: - The electronic configuration of chalcogens is
- Magnetic quantum number specifies
- Acetone and acetaldehyde are
- Helium is used in balloons in place of hydrogen because it is
- Colligative properties of solution are those properties which depend on the
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electronic configuration of chalcogens is
- Magnetic quantum number specifies
- Acetone and acetaldehyde are
- Helium is used in balloons in place of hydrogen because it is
- Colligative properties of solution are those properties which depend on the
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply