| ⇦ | 
| ⇨ |
The first ionization potentials (eV) of Be and B respectively are
Options
(a) 8.29, 9.32
(b) 9.32, 9.32
(c) 8.29, 8.29
(d) 9.32, 8.29
Correct Answer:
9.32, 8.29
Explanation:
First ionisation potential of Be is greater than boron due to following configuration ₄Be=1s²,2s² ₅B=1s²,2s²2p¹ Order of attraction of electrons towards nucleus 2s>2p, so more amount of energy is required to remove the electron with 2s-orbital in comparison to 2p orbital
Related Questions: - Which is most reactive of the following
- Which of the following reaction is endothermic
- The number of oxygen atoms in 4.4g of CO₂ is
- When a mixture of solid Nacl and solid K₂Cr₂O₇ is heated with concentrated sulphuric acid
- The ion which is not tetrahedral in shape is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Classification of Elements and Periodicity
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which is most reactive of the following
- Which of the following reaction is endothermic
- The number of oxygen atoms in 4.4g of CO₂ is
- When a mixture of solid Nacl and solid K₂Cr₂O₇ is heated with concentrated sulphuric acid
- The ion which is not tetrahedral in shape is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Classification of Elements and Periodicity (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply