| ⇦ | 
| ⇨ |
The first ionization potentials (eV) of Be and B respectively are
Options
(a) 8.29, 9.32
(b) 9.32, 9.32
(c) 8.29, 8.29
(d) 9.32, 8.29
Correct Answer:
9.32, 8.29
Explanation:
First ionisation potential of Be is greater than boron due to following configuration ₄Be=1s²,2s² ₅B=1s²,2s²2p¹ Order of attraction of electrons towards nucleus 2s>2p, so more amount of energy is required to remove the electron with 2s-orbital in comparison to 2p orbital
Related Questions: - Which one is electron deficient compound?
- Numbers of moles of K₂Cr₂O₇ reduced by one mole os Sn²⁺
- Vapour pressure of dilute aqueous solution of glucose is 750 mm of mercury at
- For a spontaneous process, entropy always
- Many transition metals and their compounds exhibit
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Classification of Elements and Periodicity
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one is electron deficient compound?
- Numbers of moles of K₂Cr₂O₇ reduced by one mole os Sn²⁺
- Vapour pressure of dilute aqueous solution of glucose is 750 mm of mercury at
- For a spontaneous process, entropy always
- Many transition metals and their compounds exhibit
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Classification of Elements and Periodicity (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply