| ⇦ | 
| ⇨ |
The ratio of area covered by second orbital to the first orbital is
Options
(a) 1 : 2
(b) 1 : 16
(c) 8 : 1
(d) 16 : 1
Correct Answer:
16 : 1
Explanation:
r(n) ∝ n² ; A(n) ∝ n⁴.
A₂ / A₁ = n₂⁴ / n⁴₁ = 2⁴ / 1⁴ = 16 / 1.
Related Questions: - The hybridization of oxygen atom in H₂O₂ is
- Which is difference between melting and boiling point of zero group elements
- Oil of winter green is
- The concentration of [H⁺] and [OH⁻] of a 0.1 M aqueous solution of 2% ionised
- For the reaction C(s) + O₂(g)
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The hybridization of oxygen atom in H₂O₂ is
- Which is difference between melting and boiling point of zero group elements
- Oil of winter green is
- The concentration of [H⁺] and [OH⁻] of a 0.1 M aqueous solution of 2% ionised
- For the reaction C(s) + O₂(g)
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply