⇦ | ⇨ |
The ratio of area covered by second orbital to the first orbital is
Options
(a) 1 : 2
(b) 1 : 16
(c) 8 : 1
(d) 16 : 1
Correct Answer:
16 : 1
Explanation:
r(n) ∝ n² ; A(n) ∝ n⁴.
A₂ / A₁ = n₂⁴ / n⁴₁ = 2⁴ / 1⁴ = 16 / 1.
Related Questions: - The sum of coordination number and oxidation number of the metal M in the complex
- Geometrical isomerism is possible in
- A bivalent metal has the equivalent weight of 12. The molecular weight
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
- The pH of 0.001 N acetic acid solution, which is 10% dissociated, is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The sum of coordination number and oxidation number of the metal M in the complex
- Geometrical isomerism is possible in
- A bivalent metal has the equivalent weight of 12. The molecular weight
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
- The pH of 0.001 N acetic acid solution, which is 10% dissociated, is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply