| ⇦ | 
| ⇨ |
Complete oxidation of 1 gm molecule of glucose gives rise to
Options
(a) 68,60,000 cal
(b) 6,86,000 cal
(c) 68,600 cal
(d) 6,800 cal
Correct Answer:
6,86,000 cal
Explanation:
1 molecule of glucose yields 56kcal/2ATP in anaerobic respiration and 686000 calories (686 kcal)/total of 38 ATP in aerobic respiration.
Related Questions: - Tapetum is found in
- Cancer cells are
- The role of meiosis
- Oxysomes of F₀ – F₁ particles occur on
- Molecule of ATP is structurally similar to the molecule of
Topics: Respiration in Plants
(184)
Subject: Biology
(4253)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Tapetum is found in
- Cancer cells are
- The role of meiosis
- Oxysomes of F₀ – F₁ particles occur on
- Molecule of ATP is structurally similar to the molecule of
Topics: Respiration in Plants (184)
Subject: Biology (4253)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply