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8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure. The molecular mass of the gas is
Options
(a) 9
(b) 18
(c) 27
(d) 36
Correct Answer:
27
Explanation:
PV = nRT = (m / M) RT ⇒ M = mRT / PV = (9.0 × 0.0821 × 300) / (1 × 8.2) = 27
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Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the rate of diffusion of CH₄ is twice of that of a gas X, then what is the molecular
- Argon gas was discovered by
- The hydrogen ion concentration in mol/dm, in a 0.2 M solution of a weak acid
- For the equilibrium, H₂O(l) ⇌ H₂O(g) at 1 atm and 298 K,
- At 27⁰C average kinetic energy of one mole of helium gas can be given
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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