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A certain mass of gas occupies a volume of 300 c.c. at 27⁰C and 620 mm pressure.The volume of this gas at 47⁰C and 640 mm pressure will be
Options
(a) 400 c.c.
(b) 350 c.c.
(c) 310 c.c.
(d) 510 c.c.
Correct Answer:
310 c.c.
Explanation:
V₁ = 300 cc, V₂ = ?, P₁ = 620 mm , P₂ = 640 mm. T₁ = 27 + 273 = 300 K, T₂ = 47 + 273 = 320. From the relationship, P₁V₁ / T₁ = P₂V₂ / T₂. ⇒ V₂ = 620 * 300 * 320 / 300 * 640 = 310 c.c
Related Questions: - A sample of CaCO₃ is 50% pure. On heating 1.12 L of CO₂ at STP is obtained
- The number of optical isomers formed by hydrogenation of the compound (CH₃)₂C=CHCH₃
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Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A sample of CaCO₃ is 50% pure. On heating 1.12 L of CO₂ at STP is obtained
- The number of optical isomers formed by hydrogenation of the compound (CH₃)₂C=CHCH₃
- Total number of isomers possible for the molecular formula C₄H₁₀O is
- Main constituents of LPG is
- Which of the following is a mixed ketone
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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