| ⇦ | 
| ⇨ |
For a reversible reaction, if we increase concentration of the reactants, then effect on equilibrium constant
Options
(a) depends on amount of concentration
(b) remains unchanged
(c) decreases
(d) increases
Correct Answer:
remains unchanged
Explanation:
For a reaction, A + B ⇌ C + D.
K(eq) = [C][D]/[A][B].
Increase in conc.of reactants will proceed the equilibrium in the forward direction giving more products. So that the equilibrium constant value remains constant and independent of concentration.
Related Questions: - The given reaction 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄ is an example of
- If KMnO₄ is reduced by oxalic caid, in an acidic medium, then oxidation number of Mn changes from
- The oxidation number of xenon in XeOF₂ is
- In the conversion of Br₂ to BrO₃⁻, the oxidation number of Br changes from
- If the equivalent weight of an element is 32, then the percentage of oxygen
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The given reaction 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄ is an example of
- If KMnO₄ is reduced by oxalic caid, in an acidic medium, then oxidation number of Mn changes from
- The oxidation number of xenon in XeOF₂ is
- In the conversion of Br₂ to BrO₃⁻, the oxidation number of Br changes from
- If the equivalent weight of an element is 32, then the percentage of oxygen
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply