The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T

The Horizontal Component Of Earths Magnetic Field At A Place Physics Question

The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T and the dip is tan⁻¹ (4/3). A metal rod of length 0.25m is placed in N-S direction and is moved at a constant speed of 10 cms⁻¹ towards the east. The emf induced in the rod will be

Options

(a) 1μV
(b) 5μV
(c) 7μV
(d) 10μV

Correct Answer:

10μV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. Force required to move a mass of 1kg at rest on a horizontal rough plane
  2. Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
  3. Time period of oscillation of a magnet is 2 sec. When it is remagnetised
  4. A particle has initial velocity(3i⃗ +4j⃗)and has acceleration (0.4i⃗ +0.3j⃗)
  5. Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.

Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*