| ⇦ | 
| ⇨ |
A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists a uniform magnetic field B, perpendicular to the plane motion, the proton will move in a circular path of radius
Options
(a) 2Em/qB
(b) √2Em/qB
(c) √Em/2qB
(d) √2Eq/qB
Correct Answer:
√2Em/qB
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
- SI unit of magnetic dipole moment is
- Which of the following particles will have minimum frequency of revolution
- When a light beam of frequency v is incident on a metal surface,
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
- SI unit of magnetic dipole moment is
- Which of the following particles will have minimum frequency of revolution
- When a light beam of frequency v is incident on a metal surface,
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply