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Which of the following oxidation states are the most characteristic for lead and tin respectiviely?
Options
(a) 2,4
(b) 4,4
(c) 2,2
(d) 4,2
Correct Answer:
2,4
Explanation:
When ns² electrons of outermost shell do not participate in bonding then these ns² electrons are called inert pair and the effect is called inert pair effect.Due to this inert pair effect Ge,Sn and Pb of group IV have a tendency to form both +4 and + 2 ions, Now the inert pair effect increases down the group, hence the stability of M²⁺ ions increases and M⁴⁺ ions decreases down the group. For this reason, Pb²⁺ is more stable than Pb⁴⁺ and Sn⁴⁺ is more stable than Sn²⁺.
Related Questions: - A nucleophile must have
- At equilibrium, the value of change in Gibb’s free energy (ΔG) is
- The IUPAC name of (CH₃)₂CH – CH₂ – CH₂Br is
- The ionisation energy of nitrogoen is more than that of oxygen because
- In which of the following compounds manganese has oxidation number equal
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A nucleophile must have
- At equilibrium, the value of change in Gibb’s free energy (ΔG) is
- The IUPAC name of (CH₃)₂CH – CH₂ – CH₂Br is
- The ionisation energy of nitrogoen is more than that of oxygen because
- In which of the following compounds manganese has oxidation number equal
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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