| ⇦ | 
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Halo alkane in the presence of alcoholic KOH undergoes
Options
(a) elimination
(b) polymerisation
(c) dimerisation
(d) substitution
Correct Answer:
elimination
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The first fractional product of petroleum from top to bottom is
- The most stable conformation of n-butane is
- A helium, molecule is two times heavier than a hydrogen molecule at 298 K
- Bhor’s theory is applicable to
- For isothermal change in the case of an ideal gas
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The first fractional product of petroleum from top to bottom is
- The most stable conformation of n-butane is
- A helium, molecule is two times heavier than a hydrogen molecule at 298 K
- Bhor’s theory is applicable to
- For isothermal change in the case of an ideal gas
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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