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An organic compound contains 49.3% carbon, 6.84% hydrogen and its vapour density is 73. Molecular formula of the compound is
Options
(a) C₃H₈O₂
(b) C₃H₁₀O
(c) C₆H₉O
(d) C₆H₁₀O₄
Correct Answer:
C₆H₁₀O₄
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of these have no unit?
- At 27⁰C latent heat of fusion of a compound is 2930 J/mol. Entropy change is
- If Avogadro number NA, is charged from 6.022 ˣ 10²³ mol⁻¹ to 6.022 ˣ 10²⁰ mol⁻¹
- Among the following sols the one which is hydrophobic is
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Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of these have no unit?
- At 27⁰C latent heat of fusion of a compound is 2930 J/mol. Entropy change is
- If Avogadro number NA, is charged from 6.022 ˣ 10²³ mol⁻¹ to 6.022 ˣ 10²⁰ mol⁻¹
- Among the following sols the one which is hydrophobic is
- The oxidation state of sulpur in sodium tetrathionate (Na₂S₄O₆) is
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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