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An organic compound contains 49.3% carbon, 6.84% hydrogen and its vapour density is 73. Molecular formula of the compound is
Options
(a) C₃H₈O₂
(b) C₃H₁₀O
(c) C₆H₉O
(d) C₆H₁₀O₄
Correct Answer:
C₆H₁₀O₄
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The correct order of decreasing acidic nature of H₂O,ROH,CH≡CH and NH₃ is
- Which of the following substances is used, in laboratory
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Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct order of decreasing acidic nature of H₂O,ROH,CH≡CH and NH₃ is
- Which of the following substances is used, in laboratory
- Which of the following compounds can exist in optically active form
- An electron with values 4,1,-1 and +1/2 for the set of four quantum numbers
- Pick out the stronger reducing agent among the following oxyacids of phosphorus
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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