| ⇦ | 
| ⇨ |
In which of the following compounds, nitrogen exhibits highest oxidation state
Options
(a) N₂H₄
(b) NH₃
(c) N₃H
(d) NH₂OH
Correct Answer:
N₃H
Explanation:
N₂H₄ ⇒ 2x + 4 (+1) = 0 ⇒ 2x + 4 = 0 ⇒ x = x -2. NH₃ ⇒ x + 3 (+1) = 0, ⇒ x = -3. N₃H ⇒ 3x + 1(+1) = 0 ⇒ 3x + 1 = 0. ⇒ x = -1/3. NH₂OH ⇒ x + 2 + 1(-2) + 1 = 0 ⇒ x + 1 = 0. ⇒ x = -1. Thus , highest oxidation state is -1/3.
Related Questions: - The stability of +1 oxidation state increases in the sequence:
- A mixture contains O₂ and N₂ in the ratio of 1 : 4 by the weight
- Terfenadine is commonly used as a
- Which of the following is expected not to yield a white precipitate
- The strongest reducing agent is
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The stability of +1 oxidation state increases in the sequence:
- A mixture contains O₂ and N₂ in the ratio of 1 : 4 by the weight
- Terfenadine is commonly used as a
- Which of the following is expected not to yield a white precipitate
- The strongest reducing agent is
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply