| ⇦ | 
| ⇨ |
A solution containing 6 g urea per litre is isotonic with a solution containing
Options
(a) 5.85 g NaCl per litre
(b) 34.2 g sucrose per litre
(c) 36.0 g glucose per litre
(d) 6.0 g sucrose per litre
Correct Answer:
34.2 g sucrose per litre
Explanation:
For isotonic solution, C₁ = C₂ or , n₁ / M₁V₁ = n₂ / M₂V₂.
Given, n₁ / M₁V₁ = 6/60 = 1/10.
For 34.2 g sucrose per litre C₂ = 34.2/342 = 1/10 . i.e. C₁ = C₂ .
Related Questions: - If the atomic number of an element is 33, it will be placed in the periodic table
- The number of unpaired electrons in 1s² 2s² 2p³ is
- Which kind of isomerism is exhibited by octahedral [Co(NH₃)₄Br₂]Cl
- Benzylamine is a stronger base than aniline because
- The reaction of phenol with alkaline chloroform gives salicylaldehyde, it is
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the atomic number of an element is 33, it will be placed in the periodic table
- The number of unpaired electrons in 1s² 2s² 2p³ is
- Which kind of isomerism is exhibited by octahedral [Co(NH₃)₄Br₂]Cl
- Benzylamine is a stronger base than aniline because
- The reaction of phenol with alkaline chloroform gives salicylaldehyde, it is
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Let wt.of sugar =w g per litre
Both will have same osmotic pressure.
Therefore,
w×R×T=6÷50× RT÷ 1
w= 34.2 g per litre