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A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
Related Questions: - In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series
- If λ₁ and λ₂ are the wavelengths of the first members of the Lyman and Paschen
- An electron in potentiometer experiences a force 2.4×10⁻¹⁹N. The length of potentiometer
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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