| ⇦ | 
| ⇨ |
One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure.
The change in internal energy of the gas during the transition is
Options
(a) -20 kJ
(b) 20 J
(c) -12 kJ
(d) 20 kJ
Correct Answer:
-20 kJ
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
- In Young’s experiment, the ratio of maximum to minimum intensities of the fringe
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
- In Young’s experiment, the ratio of maximum to minimum intensities of the fringe
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
ΔU = nCΔT
Also, T = PV/nR
Now,
ΔT = T-T => [PV – PV] / nR
ΔU = nR/¥-1 {PV- PV / nR} [here, ¥ = gamma]
(nR will be cancelled out)
We get,
{-8 x 10^3} / {2/5} = -20kJ.
Hope it helps 🙂