| ⇦ |
| ⇨ |
The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻ follow the order
Options
(a) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(b) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(c) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
(d) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
Correct Answer:
S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An aldehyde can undergo the aldol condensation having
- Maximum number of electrons in a subshell with l=3 and n=4 is
- When CO₂ is passed through solution of calcium hydroxide,Which one of the
- Alizarin belongs to the class of
- H₂O₂ reduces MnO₄⁻ ion to
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An aldehyde can undergo the aldol condensation having
- Maximum number of electrons in a subshell with l=3 and n=4 is
- When CO₂ is passed through solution of calcium hydroxide,Which one of the
- Alizarin belongs to the class of
- H₂O₂ reduces MnO₄⁻ ion to
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply