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An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62⁰C, its efficiency is doubled. Temperature of the source is
Options
(a) 37⁰C
(b) 62⁰C
(c) 99⁰C
(d) 124⁰C
Correct Answer:
99⁰C
Explanation:
Since efficiency of engine is ? = 1 – T₂ / T₁
According to the problem, 1/6 = 1 – T₂ / T₁ ……(1)
When the temperature of the sink is reudced by 62⁰C, its efficiency is doubled
2 (1/6) = 1 – T₂ – 62 / T₁ ……..(2)Solving (1) and (2) T₂ = 372 K
T₁ = 99⁰C = Temperature of source.
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Topics: Thermodynamics
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Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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