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A transistor is operated in common-emitter configuration at Vᵥ = 2 V such that a change in the base current from 100 µA to 200 µA produces a change in the collector current from 5 mA to 10 mA. The current gain is
Options
(a) 100
(b) 150
(c) 50
(d) 75
Correct Answer:
50
Explanation:
∆Iₑ = ∆Iₘ + ∆Iₙ
β = ∆Iₙ / ∆Iₘ
∆Iₙ = (10 – 5)10⁻³ = 5 x 10⁻³ A
∆Iₘ = (200 – 100)10⁻⁶ = 100 x 10⁻⁶ A
β = 5 x 10⁻³ / 100 x 10⁻⁶ = 5/100 x 1000 = 50
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A source of unknown frequency gives 4 beats/s, when sounded with a source harmonic
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- The de-broglie wavelength of an electron in 4th orbit is
- If A=3i+4j and B=7i+24j the vector having the same magnitude as B and parallel to A is
- The internal energy change in a system that has absorbed 2 kcals of heat
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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