When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental

When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental frequencies of these three segments are v₁, v₂ and v₃ respectively. The original fundamental frequency (v) of the string is

Options

(a) √v = √v₁ + √v₂ + √v₃
(b) v = v₁ + v₂ + v₃
(c) 1/v = 1/v₁ + 1/v₂ + 1/v₃
(d) 1/ √v = 1/ √v₁ + 1/ √v₂ + 1/ √v₃

Correct Answer:

1/v = 1/v₁ + 1/v₂ + 1/v₃

Explanation:

Fundamental frequency is given by v = 1/ 2l √(T / µ)
⇒ v ∞ 1/ l ⇒ P ∞ 1 / v Since, P divided into l₁, l₂ and l₃ segments.
Here, l = l₁ + l₂ + l₃
So, 1/v = 1/v₁ + 1/v₂ + 1/v₃

admin:

Related Questions

  1. A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface
  2. Two sources P and Q produce notes of frequency 660 Hz each.
  3. For non-conductors, the energy gap is
  4. A certain metallic surface is illuminated with monochromatic light of wavelength
  5. The thermo e.m.f. E in volts of a certain thermocouple is found to vary