When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is

Options

(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π

Correct Answer:

λ/2π

Explanation:

Maximum particle velocity (vₚ)ₘₐₓ = aω

where a is the amplitude of the wave and ω is the angular frequency

Wave velocity, v = λʋ

where λ is the wavelength of a wave and ʋ is a frequency of a wave.

Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π