When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy

When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is

(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K

293 cal/K

Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K

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