Three particles A,B and C are thrown from the top of a tower with the same speed.

Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speed V(A),V(B) and V(C) respectively.

Options

(a) V(A)=V(B)=V(C)
(b) V(B)>V(C)>V(A)
(c) V(A)=V(B)>V(C)
(d) V(A)>V(B)=V(C)

Correct Answer:

V(A)=V(B)>V(C)

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. A coin placed on a rotating turn table just slips,if it is placed at a distance
  2. An α-particle and a proton travel with the same velocity in a magnetic field
  3. The ratio of the numerical value of the average velocity and average speed
  4. The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
  5. The magnetic field at a point on the axis of a long solenoid having 5 turns per cm