The time period of a simple pendulum in a lift descending with constant acceleration g is

The time period of a simple pendulum in a lift descending with constant acceleration g is

Options

(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite

Correct Answer:

Infinite

Explanation:

When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.

admin:

Related Questions

  1. An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
  2. The wavelength of kα, X-rays produced by an X-ray tube 0.76Å. The atomic number
  3. A 1Ω resistance in series with an ammeter is balanced by 75 cm of potentiometer wire
  4. Suppose for some reasons, radius of earth were to shrink by 1% of present value,
  5. An electric charge 10⁻³ μC is placed at the origin (0,0) of X-Y co-ordinate system.