The shape of IF₇ molecule is

Options

(a) octahedral
(b) trigonal bipyramidal
(c) tetrahedral
(d) pentagonal bipyramidal

Correct Answer:

pentagonal bipyramidal

Explanation:

Number of hybrid orbitals,
H = 1/2 [V + M + A – C]
H = 1/2 [7 + 7 + 0 – 0]
Thus, thehybridisation of IF₇ is sp³d³ and its geometry is pentagonal bypyraminal.