The ratio of amplitude of magnetic field to the amplitude of electric field for

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:

Options

(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity

Correct Answer:

reciprocal of speed of light in vacuum

Explanation:

The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C

admin:

Related Questions

  1. The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
  2. A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
  3. Frequency of stretched string will increase by
  4. Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
  5. A ball is dropped from a high rise platform at t = 0 starting from rest