The ratio of amplitude of magnetic field to the amplitude of electric field for

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:

Options

(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity

Correct Answer:

reciprocal of speed of light in vacuum

Explanation:

The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C

admin:

Related Questions

  1. Which radiations are used in tratement of muscles ache?
  2. An astronomical telescope arranged for normal adjustment has a magnification of 6.
  3. On observing light from three different stars P, Q and R, it was found that intensity
  4. The electron drift speed is small and the change of the electron is also small
  5. An air bubble in a glass slab with refractive index 1.5 (near normal incidence)