The ratio of amplitude of magnetic field to the amplitude of electric field for

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:

Options

(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity

Correct Answer:

reciprocal of speed of light in vacuum

Explanation:

The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C

admin:

Related Questions

  1. A series R-C circuit is connected to an alternating voltage source. Consider two
  2. Consider two nuclei of the same radioactive nuclide. One of the nuclei was created
  3. 1 Wb/m² equal to
  4. The phase difference between two points seperated by 0.8 m in a wave of frequency
  5. A charge of 40 µC is given to a capacitor having capacitance C=10 µF