The ratio of amplitude of magnetic field to the amplitude of electric field for

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:

Options

(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity

Correct Answer:

reciprocal of speed of light in vacuum

Explanation:

The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C

admin:

Related Questions

  1. Magnetic induction produced at the centre of a circular loop carrying current is B.
  2. Monochromatic radiation emitted when electron on hydrogen atom
  3. A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
  4. If the minimum energy of photons needed to produce photoelectrons is 3 eV,
  5. The kinetic energy of particle moving along a circle of radius R depends