The momentum of a photon of energy 1 MeV in kg m/s will be

The momentum of a photon of energy 1 MeV in kg m/s will be

Options

(a) 5 x 10⁻²²
(b) 0.33 x 10⁶
(c) 7 x10⁻²⁴
(d) 10⁻²²

Correct Answer:

5 x 10⁻²²

Explanation:

Energy of photon E = 1 MeV

Momentum of photon p = E / c

p = E / c = (1 × 10⁶ × 1.6 × 10⁻¹⁹J) / 3 × 10⁸ ms⁻¹

= 0.53 × 10⁻²¹ = 5 × 10⁻²² kg m/s.

admin:

Related Questions

  1. A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
  2. A bar magnet with magnetic moment 2.5×10³ JT⁻¹ is rotating in horizontal plane
  3. The root mean square speed of oxygen molecule (O₂) at a certain temperature is v.
  4. An ideal gas is expanding such that PT²=constant. The coefficient of volume
  5. In a diffraction pattern due to a singleslit of width a, the first minimum is observed