The momentum of a photon of energy 1 MeV in kg m/s will be

The momentum of a photon of energy 1 MeV in kg m/s will be

Options

(a) 5 x 10⁻²²
(b) 0.33 x 10⁶
(c) 7 x10⁻²⁴
(d) 10⁻²²

Correct Answer:

5 x 10⁻²²

Explanation:

Energy of photon E = 1 MeV

Momentum of photon p = E / c

p = E / c = (1 × 10⁶ × 1.6 × 10⁻¹⁹J) / 3 × 10⁸ ms⁻¹

= 0.53 × 10⁻²¹ = 5 × 10⁻²² kg m/s.

admin:

Related Questions

  1. The displacement of particle is given by x=aₒ+(a₁t/2)-(a₂t²/3) what is acceleration?
  2. Two concentric coils each of radius equal to 2π cm are placed at right angles
  3. A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
  4. The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
  5. The velocity of a particle performing simple harmonic motion, when it passes