The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc

Options

(a) 1/2 MR²
(b) MR²
(c) 2/5 MR²
(d) 3/2 MR²

Correct Answer:

3/2 MR²

Explanation:

Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular of its plane is,
Ic = (1/2) MR²
By the theorem of parallel axes,
Therefore, moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.
I = Ic + Mh² = (1/2) MR² + MR² = (3/2) MR².