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The intensity at the maximum in a Young’s double slit experiment is I₀.

The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?

Options

(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀

Correct Answer:

I₀/2

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

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