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The horizontal range and maximum height of a projectile are equal.The angle of projection

The horizontal range and maximum height of a projectile are equal.The angle of projection is

Options

(a) θ=tan⁻¹(1/4)
(b) θ=tan⁻¹(4)
(c) θ=tan⁻¹(2)
(d) θ=45ﾟ

Correct Answer:

θ=tan⁻¹(4)

Explanation:

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