The energy required to charge a parallel plate condenser of plate separation d

The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is

Options

(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad

Correct Answer:

1/2 ε₀E²/ Ad

Explanation:

The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad

admin:

Related Questions

  1. “On flowing current in a conducting wire the magnetic field is produced around it”.
  2. A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily
  3. Radius of a soap bubble is increased from R to 2R. Work done in this process
  4. The wheel of a car is rotating at the rate of 1200 rev/min. On pressing
  5. A body undergoes no change in volume. Poisson’s ratio is