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The change in oxidation state of sulphur when sulphur dioxide is passed

The change in oxidation state of sulphur when sulphur dioxide is passed in an acidified K₂Cr₂O₇ solution is from

Options

(a) 4 to 0
(b) 4 to 2
(c) 4 to 6
(d) 6 to 4

Correct Answer:

4 to 6

Explanation:

Acidified K₂Cr₂O₇ solution oxidised SO₂ into Cr₂(SO₄)₃.
3SO₂ + K₂Cr₂O₇ + H₂O → K₂SO₄ + Cr₂(SO₄)₃ + H₂O
Oxidation of S =+4
Oxidation of (SO₄) = +6

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