Navigate

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

Options

(a) 30.2 MeV
(b) 23.6 MeV
(c) 2.2 MeV
(d) 28.0 MeV

Correct Answer:

23.6 MeV

Explanation:

Binding energy of two ₁H² nuclei = 2 (1.1 x 2) = 4.4 meV
Binding energy of one ₂He⁴ nucleus = 4 x 7.0 = 28 MeV
Energy released = 28 – 4.4 = 23.6 MeV

AIEEE2004
admin:

Related Questions

  1. In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
  2. Three capacitors each of capacitance C and of breakdown voltage V are joined in series
  3. The two ends of a rod of length L and a uniform cross-sectional area
  4. The pressure at the bottom of a tank containing a liquid does not depend on
  5. Under constant pressure, graph between P and 1/V is a