Navigate

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

Options

(a) 30.2 MeV
(b) 23.6 MeV
(c) 2.2 MeV
(d) 28.0 MeV

Correct Answer:

23.6 MeV

Explanation:

Binding energy of two ₁H² nuclei = 2 (1.1 x 2) = 4.4 meV
Binding energy of one ₂He⁴ nucleus = 4 x 7.0 = 28 MeV
Energy released = 28 – 4.4 = 23.6 MeV

AIEEE2004
admin:

Related Questions

  1. A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
  2. The mass of a lift is 2000kg. When the tension in the supporting cable is 28000N, then its acceleration is
  3. The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
  4. A 1 kg particle strikes a wall with velocity 1 m/s at an angle 30° and reflects
  5. If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum