The acceleration of an electron in an electric field of magnitude 50 V/cm,

The Acceleration Of An Electron In An Electric Field Of Physics QuestionThe Acceleration Of An Electron In An Electric Field Of Physics Question

The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is 1.76×10¹¹ C/kg will be

Options

(a) 8.8×10¹⁴ m/sec²
(b) 3×10¹³ m/sec²
(c) 5.4×10¹² m/sec²
(d) Zero

Correct Answer:

8.8×10¹⁴ m/sec²

Explanation:

Acceleration = a = eE / m

⇒ a = 1.76 × 10¹¹ × 50 × 10 ¹²

⇒ a = 8.8 × 10 ¹⁴ m/ sec²

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View Comments (1)

  • E=50v/cm
    =5000v/m
    e/m=1.76×10power-11
    F=ma
    F=qĒ
    ma=qĒ
    a= e/m×Ē
    =1.76×10 power11 × 5000
    =8.8×10 power 14 m/sec sq.

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