Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to

Options

(a) 1/R
(b) 1/√R
(c) R
(d) 1/R³/²

Correct Answer:

1/R

Explanation:

Kinetic energy of the satellite=1/2mv₀²
v₀=√GM/R
Now, Putting the value of v₀, We get,
Kinetic energy=1/2m(√GM/R)²
=1/2 GMm/R
Therefore, Kinetic energy is proportional to 1/R.