Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
Options
(a) ?ᅡᄇ √ [ R² + ( L? – 1 / C?)² ] / R
(b) ?ᅡᄇ [ R² + ( L? – 1 / C?)² ] / R
(c) ?ᅡᄇR / √ [ R² + ( L? – 1 / C?)² ]
(d) ?ᅡᄇR / [ R² + ( L? – 1 / C?)² ]
Correct Answer:
?ᅡᄇR / [ R² + ( L? – 1 / C?)² ]
Explanation:
Power dissipated in series LCR;
P = IR = / (Z) R
= ?ᅡᄇR / [ R² + ( L? – 1 / C?)² ]
where Z = √ R² + ( L? – 1 / C?)²
is called the impedance of the circuit.