In an interference experiment, third bright fringe is obtained at a point

In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?

Options

(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm

Correct Answer:

420 nm

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. To observed diffraction, the size of the obstacle
  2. The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
  3. When there is no heat change from surroundings in a system, then the process
  4. A 100Ω resistance and a capacitor of 100Ω reactance are connected in series
  5. When an input signal 1 is applied to a NOT gate, then its output is