If rope of lift breaks suddenly, the tension exerted by the surface of the lift

If rope of lift breaks suddenly, the tension exerted by the surface of the lift (a = Acceleration of lift) is

Options

(a) mg
(b) m(g+a)
(c) zero
(d) m(g-a)

Correct Answer:

zero

Explanation:

If the rope suddenly breaks, acceleration = g
So substituting in formula, tension T=m(g−a)=0

admin:

Related Questions

  1. If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
  2. A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
  3. If a solid sphere of mass 1 kg and radius 0.1 m rolls without slipping at a uniform
  4. The liquid-crystal phase of a matter is called
  5. 3 persons are initially at the 3 corners of an equilateral triangle