If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton

If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton and neutron respectively in units of u (1u = 931.5 MeV/c) and BE represents its bonding energy in MeV, then

Options

(a) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
(b) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE
(c) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE
(d) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE/c²

Correct Answer:

M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²

Explanation:

Mass defect = ZMₚ + (A – Z)Mₙ – M(A – Z)
or, B.E. / c² = ZMₚ + (A – Z)Mₙ – M(A – Z)
M(A – Z) = ZMₚ + (A – Z)Mₙ – B.E. / c²

admin:

Related Questions

  1. A spring when stretched by 2mm containing energy 4 J. If it is stretched
  2. Unit of electrical conductivity is
  3. When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles
  4. When a Daniel cell is connected in the secondary circuit of a potentiometer,
  5. Find out the angle of projection, if range is 4 times of maximum height