If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton

If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton and neutron respectively in units of u (1u = 931.5 MeV/c) and BE represents its bonding energy in MeV, then

Options

(a) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
(b) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE
(c) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE
(d) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE/c²

Correct Answer:

M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²

Explanation:

Mass defect = ZMₚ + (A – Z)Mₙ – M(A – Z)
or, B.E. / c² = ZMₚ + (A – Z)Mₙ – M(A – Z)
M(A – Z) = ZMₚ + (A – Z)Mₙ – B.E. / c²

admin:

Related Questions

  1. A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
  2. Two bullets are fired simultaneously, horizontally and with different speeds
  3. If a charge in current of 0.01 A in one coil produces a change in magnetic flux
  4. The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
  5. The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.