For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

Options

(a) (1/2)
(b) 1/√2
(c) 2
(d) √2

Correct Answer:

(1/2)

Explanation:

-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.