An electron of mass m and a photon have same energy E. The ratio of de-Broglie

An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is

Options

(a) (E/2m)¹∕₂
(b) c(2mE)¹∕₂
(c) 1/c (2m/E)¹∕₂
(d) 1/c (E/2m)¹∕₂

Correct Answer:

1/c (E/2m)¹∕₂

Explanation:

λₑ = h / √2mE,

λp = hc / E,

E = hc / λp

λₑ / λp = (h / √2mE) (E / hc)

= 1/c √(E / 2m)

=1/c (E/2m)¹∕₂

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