An electron in the hydrogen atom jumps from excited state n to the ground state

An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, the value of n is

Options

(a) 3
(b) 4
(c) 5
(d) 2

Correct Answer:

4

Explanation:

KEₘₐₓ = 10 eV ? = 2.75 eV
Total incident energy
E = ? + KEₘₐₓ = 12.75 eV
Energy is released when electron jumps from the excited state n to the ground state.
E₄ – E₁ = {-0.85 – (-13.6) eV}
= 12.75 eV value of n = 4.

admin:

Related Questions

  1. A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
  2. Two particles which are initially at rest, move towards each other
  3. A sound source is moving towards a stationary listener with 1/10th of the speed
  4. The threshold wavelength for photoelectric emission from a material is 4800 Å.
  5. A planet in a distinct solar system is 10 times more massive than the earth