Navigate

A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is

A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is

Options

(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these

Correct Answer:

50 Hz

Explanation:

Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz

AFMC2002
admin:

Related Questions

  1. A particle performing uniform circular motion has angular momentum
  2. Vectors A⃗, B⃗ and C⃗ are such that A⃗ . B⃗ = 0 and A⃗ . C⃗ = 0 Then the vector parallel
  3. Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
  4. The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
  5. Electron in hydrogen atom first jumps from third excited state to second excited