Navigate

If v is the speed of sound in air, then the shortest length of the closed pipe

If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n

Options

(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v

Correct Answer:

v / 4n

Explanation:

For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n

KA2003
admin:

Related Questions

  1. A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes
  2. In a circuit, 5% of total current passes through a galvanometer. If resistance
  3. The acceleration due to gravity at a place is π² m/sec². Then the time period
  4. In which of the follows decays, the element does not change?
  5. The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum