A transistor is operated in common-emitter configuration at Vᵥ = 2 V such that a change

A transistor is operated in common-emitter configuration at Vᵥ = 2 V such that a change in the base current from 100 µA to 200 µA produces a change in the collector current from 5 mA to 10 mA. The current gain is

Options

(a) 100
(b) 150
(c) 50
(d) 75

Correct Answer:

50

Explanation:

∆Iₑ = ∆Iₘ + ∆Iₙ
β = ∆Iₙ / ∆Iₘ
∆Iₙ = (10 – 5)10⁻³ = 5 x 10⁻³ A
∆Iₘ = (200 – 100)10⁻⁶ = 100 x 10⁻⁶ A
β = 5 x 10⁻³ / 100 x 10⁻⁶ = 5/100 x 1000 = 50

admin:

Related Questions

  1. A high altitude, a body explodes at rest into two equal fragments with one fragment
  2. If the self inductance of 500 turn coil is 125 mH, then the self inductance
  3. Which one of the following electrical meter has the smallest resistance?
  4. A particle executes simple harmonic oscillations with an amplitude
  5. If a full wave rectifier circuit is operating from 50 Hz mains, the fundamental